121=49x^2

Solution for 121=49x^2 equation:

121=49x^2

We move all terms to the left:

121-(49x^2)=0

a = -49; b = 0; c = +121;
Δ = b2-4ac
Δ = 02-4·(-49)·121
Δ = 23716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23716}=154$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-154}{2*-49}=\frac{-154}{-98}
=1+4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+154}{2*-49}=\frac{154}{-98}
=-1+4/7
$